Array Program #4

7. Read n numbers in an array, read two different numbers, search the first number in an array and replace it with another number in an array and print its index and final array.

#include <stdio.h>
int main()
{
    int array[100], x,y, i, n, count = 0;
     
        printf("Enter the number of elements in array\n");
     scanf("%d", &n);
     
     printf("Enter %d numbers\n", n);
     
     for (i = 0; i < n; i++)
        scanf("%d", &array[i]);
       
    printf("Enter n number by which you want to replace?\n");
     scanf("%d",&x);
   
     printf(" By which number?\n");
     scanf("%d",&y);
     
     for (i = 0; i < n; i++)
     {
        if (array[i] == x)
        {
             array[i]=y;
           printf("%d is present at location %d.\n", y, i+1);
           count++;
        }
     }
     if (count == 0)
        printf("%d isn't present in the array.\n", x);
     else
        printf("%d is present %d times in the array.\n", y, count);
     printf("Resultant array is\n");
     for (i=0;i<n;i++)
     {
         printf("%d\n",array[i]);
     }
}

Output

• Enter the number of elements in array
  10
  Enter 10 numbers
  12
  4
  2
  6
  4
  7
  4
  9
  13
  8
  Enter n number by which you want to replace?
  4
   By which number?
  0
  0 is present at location 2.
  0 is present at location 5.
  0 is present at location 7.
  0 is present 3 times in the array.
  Resultant array is
  12
  0
  2
  6
  0
  7
  0
  9
  13
  8
• Enter the number of elements in array
  5
  Enter 5 numbers
  23
  12
  45
  65
  20
  Enter n number by which you want to replace?
  60
   By which number?
  23
  60 isn't present in the array.
  Resultant array is
  23
  12
  45
  65
  20

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